At 25°C, what is the approximate pH of 100 mL of aqueous solution containing 0.01 mol of NaOH? Assume complete dissociation and ideal concentration behaviour.

Explanation

The hydroxide concentration is 0.01 mol / 0.100 L = 0.10 mol L⁻¹, assuming complete dissociation and ideal concentration behaviour. Thus pOH = 1. At 25°C, pH + pOH = 14, giving pH = 13.